Making any integer with four 2s (2025)

(eli.thegreenplace.net)

42 points | by germanrabbit 2 hours ago

5 comments

  • gnabgib 1 hour ago
    Popular last year (368 points, 165 comments) https://news.ycombinator.com/item?id=43145753
  • adas0693 51 minutes ago
    there is a related problem (inspired by an interview questions from ITA software, a part of Google now) that asks to find the smallest positive integer that cannot be expressed using a digit K (in [2,9]) N times in an expression that involves the four basic arithmetic operations and the parentheses: +, -, *, /, (, and ).

    to make the problem more interesting, the list of operations can be extended to include exponentiation and concatenation.

    for example, using the four basic operations for N=4, and K in [2,9], we get:

    7 cannot be computed in 4 2s; 11 cannot be computed in 4 3s; 10 cannot be computed in 4 4s; 8 cannot be computed in 4 5s; 9 cannot be computed in 4 6s; 4 cannot be computed in 4 7s; 5 cannot be computed in 4 8s; 4 cannot be computed in 4 9s;

    • genter 47 minutes ago
      Are you allowed to brute force it?
  • Arnt 1 hour ago
    Spoilsport.

    And JFYI since December is near: https://rant.gulbrandsen.priv.no/hack/advent-calendar-for-ne...

  • teo_zero 1 hour ago
    Never understood why 7 is considered difficult...

    7 = ⌈ 2.2² + 2 ⌉

    • blueblock 17 minutes ago
      Rounding spoils the fun of the puzzle.
    • AnimalMuppet 40 minutes ago
      It is difficult when the rules do not allow exponentiation.
      • Jtsummers 18 minutes ago

          7 = ⌈ 2.2 + 2 + 2⌉
        
        Would still work.